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20.02. CPP/lambda.md
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20.02. CPP/lambda.md
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---
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tags: cpp11, cpp14
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aliases:
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date: 2022-06-12
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time: 18:21:42
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description:
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---
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一個簡單的 Lamdba 運算式:
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```cpp
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[] (int x, int y) -> bool {
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return x < y;
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}
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```
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- 以中括號開頭,中括號被稱為*lamdba 導入器(lamdba introducer)*
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- 小括號裡面是*lamdba 參數列表(lambda parameter list)*
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- 如果沒有參數,小括號可以省略,`[] () {...}` 可以簡寫成 `[] {...}`
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- 箭號(`->`)後面是回傳的型別,如果沒寫就由 `return` 自動推斷
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將 Lamdba 運算式指定給變數:
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```cpp
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auto comapre = [] (int x, int y) -> bool {
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return x < y;
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};
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```
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## Lamdba的擷取子句
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以中括號開頭的 *lamdba 導入器* 可以將外部的變數傳給 Lamdba 運算式,正式名稱是「擷取子句(capture clause)」。
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`[=]` 表示它們會以值擷取(captured by value)。Scope內的變數可以在 lamdba 內使用,但是不可以改變。
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`[&]` 表示它們會以參考擷取(captured by reference)。Scope內的變數可以在 lamdba 內使用,可以改變。
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## 以值擷取(captured by value)
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假設有一段程式如下:
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```cpp
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void testLambda() {
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float notUsed = 1.0f;
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std::vector<int32_t> numlist{10, 20, 30, 50, 60};
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auto findInRange = [=](int32_t start, int32_t end) {
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for (auto num : numlist) {
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if (num >= start && num <= end) return true;
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}
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return false;
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};
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std::cout << "Result: " << findInRange(25, 35) << "\n";
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}
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```
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用`[=]`可以用來擷取 lamdba scope 範圍所及的變數,沒有在 Lamdba 運算式裡面被用到的變數就不會被擷取,例如 `float notUsed = 1.0f;`。
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另一個重點是:**被擷取的變數是不可以更改的**。例如,不能在 lambda 裡面這樣寫:
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```cpp
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auto findInRange = [=](int32_t start, int32_t end) {
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numlist.push_back(5); // ERROR!
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for (auto num : numlist) {
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if (num >= start && num <= end) return true;
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}
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return false;
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};
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```
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如果一定要在 lambda 內改變擷取的變數,那必須指名 lambda 為 `mutable`:
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```cpp
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auto findInRange = [=](int32_t start, int32_t end) mutable { // <-- assign mutable
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numlist.push_back(5);
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for (auto num : numlist) {
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if (num >= start && num <= end) return true;
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}
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return false;
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};
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```
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根據書上解釋 ,可以裡解為 compiler 會將 lamdba 編為一個 class,像是:
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```cpp
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class __Lambda8C1A5 {
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public:
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__Lambda8C1A5(const std::vector<int32_t>& arg1) : numlist(arg1) {}
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auto operator()(int32_t start, int32_t end) const { // const!
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for (auto num : numlist) {
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if (num >= start && num <= end) return true;
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}
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return false;
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}
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private:
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std::vector<int32_t> numlist;
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};
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```
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這也解釋了 lamdba 的擷取範圍與原理。而 `mutable` 則是讓 `operator()` 不為 `const`,如下:
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```cpp
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auto findInRange = [=](int32_t start, int32_t end) mutable { // <-- assign mutable
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numlist.push_back(5);
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for (auto num : numlist) {
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if (num >= start && num <= end) return true;
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}
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return false;
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};
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...
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class __Lambda8C1A5 {
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public:
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__Lambda8C1A5(const std::vector<int32_t>& arg1) : numlist(arg1) {}
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auto operator()(int32_t start, int32_t end) { // No const here
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for (auto num : numlist) {
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if (num >= start && num <= end) return true;
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}
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return false;
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}
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private:
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std::vector<int32_t> numlist;
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};
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```
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## 以值擷取特定的變數
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若只需要擷取特定的變數,那就直接在 lamdba 導入器(就是`[]`)寫入變數名稱,例如:
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```cpp
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int var1 = 10;
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int var2 = 20;
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int var3 = 30;
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auto afunc = [var1, var2] () {
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...
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};
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```
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## 以參考擷取(captured by reference)
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`[&]` 會擷取 scope 內的所有外部變數,而且可以修改:
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```cpp
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void testLambda() {
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float notUsed = 1.0f;
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std::vector<int32_t> numlist{ 10, 20, 30, 50, 60 };
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auto findInRange = [&](int32_t start, int32_t end) { // Use & here
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numlist.push_back(100); // OK
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for (auto num : numlist) {
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if (num >= start && num <= end) return true;
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}
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return false;
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};
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std::cout << "Result: " << findInRange(25, 35) << "\n";
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std::cout << "numlist: ";
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for (auto n : numlist) {
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std::cout << n << " ";
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}
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std::cout << "\n"; // Output numlist: 10 20 30 50 60 100
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}
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```
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## 以參考擷取特定的變數
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但是直接參考全部的外部變數不是好的作法,這讓你有機會做出一些意外的修改,所以請擷取有需要的變數就好:
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```cpp
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void testLambda() {
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float notUsed = 1.0f;
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std::vector<int32_t> numlist{ 10, 20, 30, 50, 60 };
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auto findInRange = [&numlist](int32_t start, int32_t end) {
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numlist.push_back(100); // OK
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for (auto num : numlist) {
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if (num >= start && num <= end) return true;
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}
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return false;
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};
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...
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}
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```
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如果有多個變數需要擷取,那就用 `,` 分開:
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```cpp
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auto findInRange = [&numlist, &var1, &var2](int32_t start, int32_t end) {
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...
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};
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```
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## 混合擷取
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以值擷取跟參考擷取也可以寫在一起:
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```cpp
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auto findInRange = [=, &numlist](int32_t start, int32_t end) {
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...
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};
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```
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上面的例子中,`numlist` 會是參考擷取,其他的外部變數則是以值擷取。
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或是:
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```cpp
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auto findInRange = [&, numlist](int32_t start, int32_t end) {
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...
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};
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```
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上面的例子中,`numlist` 會以值擷取,其他的外部變數則是參考擷取。
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但是,如果已經使用了 `=` ,就不可以再以值擷取其他變數,像是 `[=, numlist]` 就是不合法的。
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反之,如果已經使用了 `&`,就不可以再參考擷取其他變數,像是 `[&, &var1]` 就是不合法的。
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## 存取 class
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Lamdba 寫在 class 裡面的時候,不論 [[lambda#以值擷取(captured by value)|以值擷取]]或是 [[lambda#以參考擷取(captured by reference)|以參考擷取]]都沒辦法傳遞成員變數(member variable),只能傳遞 `this`,透過 `this` 來存取成員變數。例:
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```cpp
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class BigBuffer {
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public:
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void modify(int x, int y, ...) {
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auto modifyBuffer = [this] () { // Use this
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if (buffer) { // equal to this->buffer
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// do something with buffer
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}
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};
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...
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}
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private:
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uint32_t bufferSize = 0;
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std::unique_ptr<uint8_t[]> buffer = nullptr;
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};
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```
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